What is (((a^{-2})^{-1})^{-1})/((a/(a^{-1)))^2} ?

The solution to (((a^{-2})^{-1})^{-1})/((a/(a^{-1)))^2} is 1/(a^6)

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simplify (((a^{-2})^{-1})^{-1})/((a/(a^{-1)))^2}

simplify

\frac{( ( a ^{- 2} ) ^{- 1} ) ^{- 1}}{( \frac{a}{a ^{- 1}} ) ^{2}}

\frac{1}{a ^{6}}

Solution steps

\frac{( ( a ^{- 2} ) ^{- 1} ) ^{- 1}}{( \frac{a}{a ^{- 1}} ) ^{2}}

Simplify

((a^{- 2})^{- 1})^{- 1} : \frac{1}{a ^{2}}

= \frac{\frac{1}{a ^{2}}}{( \frac{a}{a ^{- 1}} ) ^{2}}

Simplify

(\frac{a}{a ^{- 1}})^{2} : a^{4}

= \frac{\frac{1}{a ^{2}}}{a ^{4}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{1}{a ^{2} a ^{4}}

Simplify

a^{2} a^{4} : a^{6}

= \frac{1}{a ^{6}}

\frac{x ^{2} + 2 x + 1}{x + 1}

3 (x + 1)^{2}

3 \div \frac{1}{4}

(1 - t)^{2}

(2 k + 1)^{2}

What is (((a^{-2})^{-1})^{-1})/((a/(a^{-1)))^2} ?
The solution to (((a^{-2})^{-1})^{-1})/((a/(a^{-1)))^2} is 1/(a^6)