What is ((x^2-16))/((x^2+9x+20))*((x+5))/((x^2-7x+12)) ?

The solution to ((x^2-16))/((x^2+9x+20))*((x+5))/((x^2-7x+12)) is 1/(x-3)

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simplify ((x^2-16))/((x^2+9x+20))*((x+5))/((x^2-7x+12))

simplify

\frac{( x ^{2} - 16 )}{( x ^{2} + 9 x + 20 )} \cdot \frac{( x + 5 )}{( x ^{2} - 7 x + 12 )}

\frac{1}{x - 3}

Solution steps

\frac{x ^{2} - 16}{x ^{2} + 9 x + 20} \cdot \frac{x + 5}{x ^{2} - 7 x + 12}

Cancel

\frac{x ^{2} - 16}{x ^{2} + 9 x + 20} : \frac{x - 4}{x + 5}

= \frac{x - 4}{x + 5} \cdot \frac{x + 5}{x ^{2} - 7 x + 12}

Cross-cancel common factor:

x + 5

= \frac{x - 4}{x ^{2} - 7 x + 12}

Factor

x^{2} - 7 x + 12 : (x - 3) (x - 4)

= \frac{x - 4}{( x - 3 ) ( x - 4 )}

Cancel the common factor:

x - 4

= \frac{1}{x - 3}

e^{\frac{1}{2} l n (x)}

\frac{4 x ^{2} + 4 x}{2 x ^{2} - 2}

- 8^{\frac{1}{3}}

\frac{1}{3} \times 2

\frac{20}{2}

What is ((x^2-16))/((x^2+9x+20))*((x+5))/((x^2-7x+12)) ?
The solution to ((x^2-16))/((x^2+9x+20))*((x+5))/((x^2-7x+12)) is 1/(x-3)