What is 1/2 (8x^2+4x-2)-1/3 (6x^2+3x-9) ?

The solution to 1/2 (8x^2+4x-2)-1/3 (6x^2+3x-9) is 2x^2+x+2

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simplify 1/2 (8x^2+4x-2)-1/3 (6x^2+3x-9)

simplify

\frac{1}{2} (8 x^{2} + 4 x - 2) - \frac{1}{3} (6 x^{2} + 3 x - 9)

2 x^{2} + x + 2

Solution steps

\frac{1}{2} (8 x^{2} + 4 x - 2) - \frac{1}{3} (6 x^{2} + 3 x - 9)

Expand

\frac{1}{2} (8 x^{2} + 4 x - 2) : 4 x^{2} + 2 x - 1

= 4 x^{2} + 2 x - 1 - \frac{1}{3} (6 x^{2} + 3 x - 9)

Expand

- \frac{1}{3} (6 x^{2} + 3 x - 9) : - 2 x^{2} - x + 3

= 4 x^{2} + 2 x - 1 - 2 x^{2} - x + 3

Group like terms

= 4 x^{2} - 2 x^{2} + 2 x - x - 1 + 3

Add similar elements:

4 x^{2} - 2 x^{2} = 2 x^{2}

= 2 x^{2} + 2 x - x - 1 + 3

Add similar elements:

2 x - x = x

= 2 x^{2} + x - 1 + 3

Add the numbers:

- 1 + 3 = 2

= 2 x^{2} + x + 2

\frac{3}{4} \div \frac{5}{6}

(m - 2) (m + 15)

(- 3 y^{2} - 5 y - 2) + (- 7 y^{2} + 5 y + 2)

lo g_{10} (60)

lo g_{10} (64)

What is 1/2 (8x^2+4x-2)-1/3 (6x^2+3x-9) ?
The solution to 1/2 (8x^2+4x-2)-1/3 (6x^2+3x-9) is 2x^2+x+2