What is expand (2x+1)(x-2)(x+3) ?

The solution to expand (2x+1)(x-2)(x+3) is 2x^3+3x^2-11x-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x+1)(x-2)(x+3)

expand

(2 x + 1) (x - 2) (x + 3)

2 x^{3} + 3 x^{2} - 11 x - 6

Solution steps

(2 x + 1) (x - 2) (x + 3)

Expand

(2 x + 1) (x - 2) (x + 3) : (2 x^{2} - 3 x - 2) (x + 3)

= (2 x^{2} - 3 x - 2) (x + 3)

Distribute parentheses

= 2 x^{2} x + 2 x^{2} \cdot 3 - 3 xx - 3 x \cdot 3 - 2 x - 2 \cdot 3

Simplify

2 x^{2} x + 2 x^{2} \cdot 3 - 3 xx - 3 x \cdot 3 - 2 x - 2 \cdot 3 : 2 x^{3} + 3 x^{2} - 11 x - 6

= 2 x^{3} + 3 x^{2} - 11 x - 6

\frac{2}{3} lo g_{10} (\frac{1 0 ^{12}}{1 0 ^{4.4}})

\frac{x ^{5} + 243}{x + 3}

\frac{9}{81}

(2 t^{- 3})^{- 2}

(3 x - 1) (x^{2} + 4 x - 5)

What is expand (2x+1)(x-2)(x+3) ?
The solution to expand (2x+1)(x-2)(x+3) is 2x^3+3x^2-11x-6