What is ((\frac{2^{-4})/(2^{-4)})}{2^{-5}} ?

The solution to ((\frac{2^{-4})/(2^{-4)})}{2^{-5}} is 32

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simplify ((\frac{2^{-4})/(2^{-4)})}{2^{-5}}

simplify

\frac{( \frac{2 ^{- 4}}{2 ^{- 4}} )}{2 ^{- 5}}

32

Solution steps

\frac{\frac{2 ^{- 4}}{2 ^{- 4}}}{2 ^{- 5}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{2 ^{- 4}}{2 ^{- 4} \cdot 2 ^{- 5}}

Cancel the common factor:

2^{- 4}

= \frac{1}{2 ^{- 5}}

2^{- 5} = \frac{1}{32}

= \frac{1}{\frac{1}{32}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{32}{1}

Divide the numbers:

\frac{32}{1} = 32

= 32

6 15 y^{4} \cdot 2 20 y^{2}

5 x^{2} + 33 x + 18

\frac{15}{13}

\frac{x ^{3} + 3 x ^{2}}{3 x}

- 3 x - 2 x

What is ((\frac{2^{-4})/(2^{-4)})}{2^{-5}} ?
The solution to ((\frac{2^{-4})/(2^{-4)})}{2^{-5}} is 32