What are the solutions to the equation x^2-12x=-11 ?

The solutions to the equation x^2-12x=-11 are x=11,x=1

Find the zeros of x^2-12x=-11

The zeros of x^2-12x=-11 are x=11,x=1

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x^{2} - 12 x = - 11

x = 11, x = 1

Solution steps

x^{2} - 12 x = - 11

Move

11

to the left side

x^{2} - 12 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 11 = 10

x_{1, 2} = \frac{- ( - 12 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 10}{2 \cdot 1}

x = \frac{- ( - 12 ) + 10}{2 \cdot 1} : 11

x = \frac{- ( - 12 ) - 10}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 11, x = 1

lo g_{1} (2) = 3

\frac{12 q ^{- 3}}{( 3 p ^{4} q ^{- 3} ) ^{- 4}}

3 x^{2} - x - 2

6 x^{2} + 7 x - 20 = 0

\frac{3}{8} + \frac{1}{4}

What are the solutions to the equation x^2-12x=-11 ?
The solutions to the equation x^2-12x=-11 are x=11,x=1
Find the zeros of x^2-12x=-11
The zeros of x^2-12x=-11 are x=11,x=1