What are the solutions to the equation x^2-5x+12=0 ?

The solutions to the equation x^2-5x+12=0 are x= 5/2+i(sqrt(23))/2 ,x= 5/2-i(sqrt(23))/2

Find the zeros of x^2-5x+12=0

The zeros of x^2-5x+12=0 are x= 5/2+i(sqrt(23))/2 ,x= 5/2-i(sqrt(23))/2

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x^{2} - 5 x + 12 = 0

x = \frac{5}{2} + i \frac{23}{2}, x = \frac{5}{2} - i \frac{23}{2}

Solution steps

x^{2} - 5 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

(- 5)^{2} - 4 \cdot 1 \cdot 12 : 23 i

x_{1, 2} = \frac{- ( - 5 ) \pm 23 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 23 i}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 23 i}{2 \cdot 1}

x = \frac{- ( - 5 ) + 23 i}{2 \cdot 1} : \frac{5}{2} + i \frac{23}{2}

x = \frac{- ( - 5 ) - 23 i}{2 \cdot 1} : \frac{5}{2} - i \frac{23}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{23}{2}, x = \frac{5}{2} - i \frac{23}{2}

144 y^{2} - 196

2 - 3

1 \geq - x - 9

- x > 5

1 - 4 a^{2}

What are the solutions to the equation x^2-5x+12=0 ?
The solutions to the equation x^2-5x+12=0 are x= 5/2+i(sqrt(23))/2 ,x= 5/2-i(sqrt(23))/2
Find the zeros of x^2-5x+12=0
The zeros of x^2-5x+12=0 are x= 5/2+i(sqrt(23))/2 ,x= 5/2-i(sqrt(23))/2