What are the solutions to the equation x^2+2x=63 ?

The solutions to the equation x^2+2x=63 are x=7,x=-9

Find the zeros of x^2+2x=63

The zeros of x^2+2x=63 are x=7,x=-9

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x^{2} + 2 x = 63

x = 7, x = - 9

Solution steps

x^{2} + 2 x = 63

Move

63

to the left side

x^{2} + 2 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 63 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 63) = 16

x_{1, 2} = \frac{- 2 \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 16}{2 \cdot 1}, x_{2} = \frac{- 2 - 16}{2 \cdot 1}

x = \frac{- 2 + 16}{2 \cdot 1} : 7

x = \frac{- 2 - 16}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 7, x = - 9

7 x + 5 = 9 x + 3

\frac{1}{x} + \frac{1}{x + 1} \geq \frac{2}{x + 2}

\frac{1}{x + 5} > - 2

3 w + 2 w = 20

6 = - \frac{3}{2} x + 3

What are the solutions to the equation x^2+2x=63 ?
The solutions to the equation x^2+2x=63 are x=7,x=-9
Find the zeros of x^2+2x=63
The zeros of x^2+2x=63 are x=7,x=-9