What are the solutions to the equation x^2+x-600=0 ?

The solutions to the equation x^2+x-600=0 are x=24,x=-25

Find the zeros of x^2+x-600=0

The zeros of x^2+x-600=0 are x=24,x=-25

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x^{2} + x - 600 = 0

x = 24, x = - 25

Solution steps

x^{2} + x - 600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 600 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 600) = 49

x_{1, 2} = \frac{- 1 \pm 49}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 49}{2 \cdot 1}, x_{2} = \frac{- 1 - 49}{2 \cdot 1}

x = \frac{- 1 + 49}{2 \cdot 1} : 24

x = \frac{- 1 - 49}{2 \cdot 1} : - 25

The solutions to the quadratic equation are:

x = 24, x = - 25

2 x - 3 \leq 5

4 y^{12} - 41 y^{7} - 33 y^{2}

- 16 (6)^{2} + x (6) + 3 = 0

ln ∣ 1 ∣

\frac{x + 1}{x - 1} + 2 \geq 0

What are the solutions to the equation x^2+x-600=0 ?
The solutions to the equation x^2+x-600=0 are x=24,x=-25
Find the zeros of x^2+x-600=0
The zeros of x^2+x-600=0 are x=24,x=-25