What are the solutions to the equation t^2=1+16t ?

The solutions to the equation t^2=1+16t are t=8+sqrt(65),t=8-sqrt(65)

Find the zeros of t^2=1+16t

The zeros of t^2=1+16t are t=8+sqrt(65),t=8-sqrt(65)

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t^{2} = 1 + 16 t

t = 8 + 65, t = 8 - 65

Solution steps

t^{2} = 1 + 16 t

Move

16 t

to the left side

t^{2} - 16 t = 1

Move

1

to the left side

t^{2} - 16 t - 1 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 1) = 265

t_{1, 2} = \frac{- ( - 16 ) \pm 2 65}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 16 ) + 2 65}{2 \cdot 1}, t_{2} = \frac{- ( - 16 ) - 2 65}{2 \cdot 1}

t = \frac{- ( - 16 ) + 2 65}{2 \cdot 1} : 8 + 65

t = \frac{- ( - 16 ) - 2 65}{2 \cdot 1} : 8 - 65

The solutions to the quadratic equation are:

t = 8 + 65, t = 8 - 65

35 + 0.22 x \leq 90

n - 6 > 1 or \frac{3}{4} n \geq 6

5 x = 0

9 x (x - 3) < 3 (3 x - 1) (x - 4)

m^{2} + 5 = 0

What are the solutions to the equation t^2=1+16t ?
The solutions to the equation t^2=1+16t are t=8+sqrt(65),t=8-sqrt(65)
Find the zeros of t^2=1+16t
The zeros of t^2=1+16t are t=8+sqrt(65),t=8-sqrt(65)