What are the solutions to the equation roots y=3x^3-3x ?

The solutions to the equation roots y=3x^3-3x are x=0,x=-1,x=1

Find the zeros of roots y=3x^3-3x

The zeros of roots y=3x^3-3x are x=0,x=-1,x=1

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roots

y = 3 x^{3} - 3 x

x = 0, x = - 1, x = 1

Solution steps

3 x^{3} - 3 x

The roots are the intercepts with the x-axis

(y = 0)

3 x^{3} - 3 x = 0

Factor

3 x^{3} - 3 x : 3 x (x + 1) (x - 1)

3 x (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or x - 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = 0, x = - 1, x = 1

Q u a d r a t i c^{0.3}

Q u a d r a t i c (- 2, - 9)

Q u a d r a t i c (3, - 9)

Q u a d r a t i c (36.4)

x^{2} - 2 x - 24 > 0

What are the solutions to the equation roots y=3x^3-3x ?
The solutions to the equation roots y=3x^3-3x are x=0,x=-1,x=1
Find the zeros of roots y=3x^3-3x
The zeros of roots y=3x^3-3x are x=0,x=-1,x=1