What are the solutions to the equation roots x^2+2x-5=0 ?

The solutions to the equation roots x^2+2x-5=0 are x=-1+sqrt(6),x=-1-sqrt(6)

Find the zeros of roots x^2+2x-5=0

The zeros of roots x^2+2x-5=0 are x=-1+sqrt(6),x=-1-sqrt(6)

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roots

x^{2} + 2 x - 5 = 0

x = - 1 + 6, x = - 1 - 6

Solution steps

x^{2} + 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 5) = 26

x_{1, 2} = \frac{- 2 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 6}{2 \cdot 1}

x = \frac{- 2 + 2 6}{2 \cdot 1} : - 1 + 6

x = \frac{- 2 - 2 6}{2 \cdot 1} : - 1 - 6

The solutions to the quadratic equation are:

x = - 1 + 6, x = - 1 - 6

\frac{( 14 - 13 )}{( 14 + 13 )}

5 x^{5} - 9 x^{3} + 2 x^{11} + 6

\frac{( 20 270 )}{( 4 3 )}

4 \cdot \frac{75}{49} - \frac{( 8 )}{( 18 )}

9 x^{3} + 3 x^{8} + 6 x^{7} + 5 x^{6} - 7 x^{5}

What are the solutions to the equation roots x^2+2x-5=0 ?
The solutions to the equation roots x^2+2x-5=0 are x=-1+sqrt(6),x=-1-sqrt(6)
Find the zeros of roots x^2+2x-5=0
The zeros of roots x^2+2x-5=0 are x=-1+sqrt(6),x=-1-sqrt(6)