What is the integral of (25)/(x^{3/2)} ?

The integral of (25)/(x^{3/2)} is -(50)/(x^{1/2)}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (25)/(x^{3/2)}

\int \frac{25}{x ^{\frac{3}{2}}} d x

- \frac{50}{x ^{\frac{1}{2}}} + C

Solution steps

\int \frac{25}{x ^{\frac{3}{2}}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 25 \cdot \int \frac{1}{x ^{\frac{3}{2}}} d x

Apply the Power Rule

: - \frac{2}{x ^{\frac{1}{2}}}

= 25 (- \frac{2}{x ^{\frac{1}{2}}})

Simplify

25 (- \frac{2}{x ^{\frac{1}{2}}}) : - \frac{50}{x ^{\frac{1}{2}}}

= - \frac{50}{x ^{\frac{1}{2}}}

Add a constant to the solution

= - \frac{50}{x ^{\frac{1}{2}}} + C

\int x \cdot 2^{x^{2}} d x

f^{'} (x)

\int x sec^{2} (4 x) d x

f (x) = (x^{2} - 15)^{7}, at x = 4

x \frac{d y}{d x} + 2 y = 6 x^{2} y

What is the integral of (25)/(x^{3/2)} ?
The integral of (25)/(x^{3/2)} is -(50)/(x^{1/2)}+C