What is (\partial)/(\partial y)(sin(x)sin(y)) ?

The answer to (\partial)/(\partial y)(sin(x)sin(y)) is sin(x)cos(y)

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(\partial)/(\partial y)(sin(x)sin(y))

\frac{\partial}{\partial y} (sin (x) sin (y))

sin (x) cos (y)

Solution steps

\frac{\partial}{\partial y} (sin (x) sin (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (x) \frac{\partial}{\partial y} (sin (y))

Apply the common derivative:

\frac{\partial}{\partial y} (sin (y)) = cos (y)

= sin (x) cos (y)

(x + y) d x - (x - y) d y = 0, y (1) = 0

\int \frac{s}{s ^{2} + 6 s + 11} d s

f (x) = 4 x - 3

\int - 2 cos (2 x) d x

x \to \frac{4}{π} lim (cos (x))

What is (\partial)/(\partial y)(sin(x)sin(y)) ?
The answer to (\partial)/(\partial y)(sin(x)sin(y)) is sin(x)cos(y)