What is (\partial)/(\partial x)(sin(y)cos(x)) ?

The answer to (\partial)/(\partial x)(sin(y)cos(x)) is -sin(y)sin(x)

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(\partial)/(\partial x)(sin(y)cos(x))

\frac{\partial}{\partial x} (sin (y) cos (x))

- sin (y) sin (x)

Solution steps

\frac{\partial}{\partial x} (sin (y) cos (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (y) \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= sin (y) (- sin (x))

Simplify

= - sin (y) sin (x)

- 8 x^{2} + 5

\int \frac{4 t}{1 - 16 t ^{4}} d t

\int sin (t) sec^{5} (t) d t

x \to 0 lim ((x) x)

\int arccos (\frac{1 + x}{2}) d x

What is (\partial)/(\partial x)(sin(y)cos(x)) ?
The answer to (\partial)/(\partial x)(sin(y)cos(x)) is -sin(y)sin(x)