What is the derivative of f(x)=(e^x)/(2x+1) ?

The derivative of f(x)=(e^x)/(2x+1) is (2e^xx-e^x)/((2x+1)^2)

What is the first derivative of f(x)=(e^x)/(2x+1) ?

The first derivative of f(x)=(e^x)/(2x+1) is (2e^xx-e^x)/((2x+1)^2)

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derivative of

f (x) = \frac{e ^{x}}{2 x + 1}

\frac{2 e ^{x} x - e ^{x}}{( 2 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{e ^{x}}{2 x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( e ^{x} ) ( 2 x + 1 ) - \frac{d}{d x} ( 2 x + 1 ) e ^{x}}{( 2 x + 1 ) ^{2}}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (2 x + 1) = 2

= \frac{e ^{x} ( 2 x + 1 ) - 2 e ^{x}}{( 2 x + 1 ) ^{2}}

Expand

e^{x} (2 x + 1) - 2 e^{x} : 2 e^{x} x - e^{x}

= \frac{2 e ^{x} x - e ^{x}}{( 2 x + 1 ) ^{2}}

y^{^{''}} + 11 y^{^{'}} + 30 y = 0

f (x, y) = x^{2} + y^{2}

ln (16 x)

y = a^{x}

f (x) = 3 - 4 x^{2}, (2, - 13)

What is the derivative of f(x)=(e^x)/(2x+1) ?
The derivative of f(x)=(e^x)/(2x+1) is (2e^xx-e^x)/((2x+1)^2)
What is the first derivative of f(x)=(e^x)/(2x+1) ?
The first derivative of f(x)=(e^x)/(2x+1) is (2e^xx-e^x)/((2x+1)^2)