What is the tangent of f(x)= 2/(4-x),\at x=-1 ?

The tangent of f(x)= 2/(4-x),\at x=-1 is y= 2/25 x+12/25

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tangent of f(x)= 2/(4-x),\at x=-1

tangent of

f (x) = \frac{2}{4 - x}, at x = - 1

y = \frac{2}{25} x + \frac{12}{25}

Solution steps

Find the tangent point:

(- 1, \frac{2}{5})

Find the slope of

f (x) = \frac{2}{4 - x} : \frac{df ( x )}{d x} = \frac{2}{( 4 - x ) ^{2}}

Compute the slope of

f (x) = \frac{2}{4 - x}

x = - 1 : m = \frac{2}{25}

Find the line with slope m=

\frac{2}{25}

and passing through

(- 1, \frac{2}{5}) : y = \frac{2}{25} x + \frac{12}{25}

y = \frac{2}{25} x + \frac{12}{25}

(sin^{2} (x))^{^{'}}

\frac{d}{d x} (4 x^{\frac{1}{3}})

5 x - x^{2}, 0

h \to 0 lim (h)

2 x^{2} y + x^{3} (\frac{d y}{d x}) = 1

What is the tangent of f(x)= 2/(4-x),\at x=-1 ?
The tangent of f(x)= 2/(4-x),\at x=-1 is y= 2/25 x+12/25