What is the limit as x approaches 1 of (4x+3)/(2x+1) ?

The limit as x approaches 1 of (4x+3)/(2x+1) is 7/3

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limit as x approaches 1 of (4x+3)/(2x+1)

x \to 1 lim (\frac{4 x + 3}{2 x + 1})

\frac{7}{3}

Decimal Notation

2.33333 \dots

Solution steps

x \to 1 lim (\frac{4 x + 3}{2 x + 1})

Plug in the value

x = 1

= \frac{4 \cdot 1 + 3}{2 \cdot 1 + 1}

Simplify

= \frac{7}{3}

n = 1 \sum \infty 4 \cdot (\frac{4}{7})^{n}

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f (x) = 5 x (sin (x) + cos (x))

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\frac{\partial}{\partial y} (x y e^{y} + e^{y} sin (x))

What is the limit as x approaches 1 of (4x+3)/(2x+1) ?
The limit as x approaches 1 of (4x+3)/(2x+1) is 7/3