What is the derivative of f(x)=sqrt(x+8) ?

The derivative of f(x)=sqrt(x+8) is 1/(2sqrt(x+8))

What is the first derivative of f(x)=sqrt(x+8) ?

The first derivative of f(x)=sqrt(x+8) is 1/(2sqrt(x+8))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = x + 8

\frac{1}{2 x + 8}

Solution steps

\frac{d}{d x} (x + 8)

Apply the chain rule:

\frac{1}{2 x + 8} \frac{d}{d x} (x + 8)

= \frac{1}{2 x + 8} \frac{d}{d x} (x + 8)

\frac{d}{d x} (x + 8) = 1

= \frac{1}{2 x + 8} \cdot 1

Simplify

= \frac{1}{2 x + 8}

\int t ln (1 + t) d t

\int_{- 8}^{0} (\frac{y}{8} + y + 9) d y

x \to \infty lim (x + 9)

\int \frac{1}{x ^{2} + 3 x + 3} d x

y^{''} (x) - 3 y^{'} (x) + 2 y = \frac{1}{1 + e ^{- x}}

What is the derivative of f(x)=sqrt(x+8) ?
The derivative of f(x)=sqrt(x+8) is 1/(2sqrt(x+8))
What is the first derivative of f(x)=sqrt(x+8) ?
The first derivative of f(x)=sqrt(x+8) is 1/(2sqrt(x+8))