What is the asymptotes of f(x)=((x^3+1))/(x^2-1) ?

The asymptotes of f(x)=((x^3+1))/(x^2-1) is Vertical: x=1,Slant: y=x

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asymptotes of f(x)=((x^3+1))/(x^2-1)

asymptotes

f (x) = \frac{( x ^{3} + 1 )}{x ^{2} - 1}

Vertical : x = 1, Slant : y = x

Solution steps

Vertical asymptotes of

\frac{x ^{3} + 1}{x ^{2} - 1} : x = 1

Horizontal Asymptotes of

\frac{x ^{3} + 1}{x ^{2} - 1} :

None

Slant Asymptotes of

\frac{x ^{3} + 1}{x ^{2} - 1} : y = x

Vertical : x = 1, Slant : y = x

f (x) = \frac{1}{2} x - \frac{1}{3}

f (x) = \frac{4 x}{7}

f (x) = \frac{9 - x}{x - 7}

f (x) = \frac{4}{x ^{2} - 4}

\frac{x ^{3}}{x ^{3} + 1}

What is the asymptotes of f(x)=((x^3+1))/(x^2-1) ?
The asymptotes of f(x)=((x^3+1))/(x^2-1) is Vertical: x=1,Slant: y=x