What is the domain of f(x)= x/(sqrt(x^2-9)) ?

The domain of f(x)= x/(sqrt(x^2-9)) is x 3

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domain of f(x)= x/(sqrt(x^2-9))

domain

f (x) = \frac{x}{x ^{2} - 9}

x < - 3 or x > 3

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

x < - 3 or x > 3

f (x) = \frac{x - 2}{2 x - 4}

f (x) = \frac{2 x}{x + 7}

f (x) = x^{2} - 4

4 - x^{2} - x + 1

\frac{2 x ^{2} + x - 15}{5 x ^{2} - 28 x + 15}

What is the domain of f(x)= x/(sqrt(x^2-9)) ?
The domain of f(x)= x/(sqrt(x^2-9)) is x<-3\lor x>3