What is the inverse of f(x)= 1/4 x^3+8 ?

The inverse of f(x)= 1/4 x^3+8 is cube root of 4x-32

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inverse of f(x)= 1/4 x^3+8

inverse

f (x) = \frac{1}{4} x^{3} + 8

Solution steps

y = \frac{1}{4} x^{3} + 8

Replace

x

with

y

x = \frac{1}{4} y^{3} + 8

Solve for

y, x = \frac{1}{4} y^{3} + 8

(x - 2) e^{x}

f (x) = \frac{7}{5 x + 7}

\frac{2 x ^{2} - x - 7}{x ^{2} + 9}

lo g_{\frac{1}{2}} (- x + 2) + 5

(2, 1), (10, 9)

What is the inverse of f(x)= 1/4 x^3+8 ?
The inverse of f(x)= 1/4 x^3+8 is cube root of 4x-32