What is the domain of (8t)/(4t^2+8t) ?

The domain of (8t)/(4t^2+8t) is t 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (8t)/(4t^2+8t)

domain

\frac{8 t}{4 t ^{2} + 8 t}

t < - 2 or - 2 < t < 0 or t > 0

Solution steps

Find undefined (singularity) points:

t = 0, t = - 2

The function domain

t < - 2 or - 2 < t < 0 or t > 0

9 - x

f (x) = x^{4} - 32 x^{2} + 5

y = 10 x + 2, (6, 5)

f (x) = \frac{x - 3}{x ^{2} - 5 x + 6}

f (x) = \frac{5}{x - 7}

What is the domain of (8t)/(4t^2+8t) ?
The domain of (8t)/(4t^2+8t) is t<-2\lor-2<t<0\lor t>0