What is the domain of f(x)=sqrt(9-x^2)-sqrt(x^2-4) ?

The domain of f(x)=sqrt(9-x^2)-sqrt(x^2-4) is -3<= x<=-2\lor 2<= x<= 3

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domain of f(x)=sqrt(9-x^2)-sqrt(x^2-4)

domain

f (x) = 9 - x^{2} - x^{2} - 4

- 3 \leq x \leq - 2 or 2 \leq x \leq 3

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq - 2 or 2 \leq x \leq 3

The function domain

- 3 \leq x \leq - 2 or 2 \leq x \leq 3

f (x) = x^{2} + y = 16

(- 2, - 5), (- 4, 3)

f (x) = \frac{9}{25 - x ^{2}}

2 t

What is the domain of f(x)=sqrt(9-x^2)-sqrt(x^2-4) ?
The domain of f(x)=sqrt(9-x^2)-sqrt(x^2-4) is -3<= x<=-2\lor 2<= x<= 3