What is the inverse of f(x)=2x^2-4x-5 ?

The inverse of f(x)=2x^2-4x-5 is (4+sqrt(8x+56))/4 ,(4-sqrt(8x+56))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=2x^2-4x-5

inverse

f (x) = 2 x^{2} - 4 x - 5

\frac{4 + 8 x + 56}{4}, \frac{4 - 8 x + 56}{4}

Solution steps

y = 2 x^{2} - 4 x - 5

Replace

x

with

y

x = 2 y^{2} - 4 y - 5

Solve for

y, x = 2 y^{2} - 4 y - 5

\frac{4 + 8 x + 56}{4}, \frac{4 - 8 x + 56}{4}

\frac{9}{x + 2}

f (x) = \frac{x}{x ^{2} + 1}

y = \frac{3}{2} x + 2

f (x) = - 0.1 t^{2} + 0.8 t + 98.8

f (x) = \frac{x ^{2} - 6 x + 5}{x - 5}

What is the inverse of f(x)=2x^2-4x-5 ?
The inverse of f(x)=2x^2-4x-5 is (4+sqrt(8x+56))/4 ,(4-sqrt(8x+56))/4