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Find three consecutive even integers such that the sum of the smallest integer and twice the median integer is 20 more than the largest integer.

Solution

Find three consecutive even integers such that the sum of the smallest integer and twice the median integer is 20 more than the largest integer.

Solution

The numbers : 10, 12, 14

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

A.T.Q.:

x + 2 (x + 2) = 20 + x + 4

Solve

x + 2 (x + 2) = 20 + x + 4 : x = 10

x + 2 = 10 + 2 = 12

x + 4 = 10 + 4 = 14

The numbers : 10, 12, 14

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