What are the solutions to the equation 6x(x-1)=12-7x ?

The solutions to the equation 6x(x-1)=12-7x are x= 4/3 ,x=-3/2

Find the zeros of 6x(x-1)=12-7x

The zeros of 6x(x-1)=12-7x are x= 4/3 ,x=-3/2

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6 x (x - 1) = 12 - 7 x

x = \frac{4}{3}, x = - \frac{3}{2}

Decimal Notation

x = 1.33333 \dots, x = - 1.5

Solution steps

6 x (x - 1) = 12 - 7 x

Expand

6 x (x - 1) : 6 x^{2} - 6 x

6 x^{2} - 6 x = 12 - 7 x

Move

7 x

to the left side

6 x^{2} + x = 12

Move

12

to the left side

6 x^{2} + x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 12 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 12) = 17

x_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 17}{2 \cdot 6}, x_{2} = \frac{- 1 - 17}{2 \cdot 6}

x = \frac{- 1 + 17}{2 \cdot 6} : \frac{4}{3}

x = \frac{- 1 - 17}{2 \cdot 6} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - \frac{3}{2}

\frac{( 3 x ^{5} y ^{3} ) ^{5}}{( 6 x ^{10} y ^{7} ) ^{2}}

i^{51}

216 + 27 y^{12}

6^{2} - 5 (6) - 3

\frac{x}{4} > - 4.1

What are the solutions to the equation 6x(x-1)=12-7x ?
The solutions to the equation 6x(x-1)=12-7x are x= 4/3 ,x=-3/2
Find the zeros of 6x(x-1)=12-7x
The zeros of 6x(x-1)=12-7x are x= 4/3 ,x=-3/2