What are the solutions to the equation 5x^2+10x-3=0 ?

The solutions to the equation 5x^2+10x-3=0 are x=(-5+2sqrt(10))/5 ,x=-(5+2sqrt(10))/5

Find the zeros of 5x^2+10x-3=0

The zeros of 5x^2+10x-3=0 are x=(-5+2sqrt(10))/5 ,x=-(5+2sqrt(10))/5

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5 x^{2} + 10 x - 3 = 0

x = \frac{- 5 + 2 10}{5}, x = - \frac{5 + 2 10}{5}

Decimal Notation

x = 0.26491 \dots, x = - 2.26491 \dots

Solution steps

5 x^{2} + 10 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

1 0^{2} - 4 \cdot 5 (- 3) = 410

x_{1, 2} = \frac{- 10 \pm 4 10}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 10 + 4 10}{2 \cdot 5}, x_{2} = \frac{- 10 - 4 10}{2 \cdot 5}

x = \frac{- 10 + 4 10}{2 \cdot 5} : \frac{- 5 + 2 10}{5}

x = \frac{- 10 - 4 10}{2 \cdot 5} : - \frac{5 + 2 10}{5}

The solutions to the quadratic equation are:

x = \frac{- 5 + 2 10}{5}, x = - \frac{5 + 2 10}{5}

2 x^{2} - 8 x + 3 = 0

(\frac{1}{81})^{- \frac{3}{4}}

d^{2} + 9 = 0

7 x^{2} - 28 x = 0

\frac{k}{2} > 4

What are the solutions to the equation 5x^2+10x-3=0 ?
The solutions to the equation 5x^2+10x-3=0 are x=(-5+2sqrt(10))/5 ,x=-(5+2sqrt(10))/5
Find the zeros of 5x^2+10x-3=0
The zeros of 5x^2+10x-3=0 are x=(-5+2sqrt(10))/5 ,x=-(5+2sqrt(10))/5