What is x^{-3}my^{-4}z^{-3} ?

The solution to x^{-3}my^{-4}z^{-3} is m/(x^3y^4z^3)

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simplify x^{-3}my^{-4}z^{-3}

simplify

x^{- 3} m y^{- 4} z^{- 3}

\frac{m}{x ^{3} y ^{4} z ^{3}}

Solution steps

x^{- 3} m y^{- 4} z^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 3} = \frac{1}{x ^{3}}

= \frac{1}{x ^{3}} m y^{- 4} z^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

y^{- 4} = \frac{1}{y ^{4}}

= \frac{1}{x ^{3}} m \frac{1}{y ^{4}} z^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

z^{- 3} = \frac{1}{z ^{3}}

= \frac{1}{x ^{3}} m \frac{1}{y ^{4}} \cdot \frac{1}{z ^{3}}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{1 \cdot m \cdot 1 \cdot 1}{x ^{3} y ^{4} z ^{3}}

Simplify

1 \cdot m \cdot 1 \cdot 1 : m

= \frac{m}{x ^{3} y ^{4} z ^{3}}

72 9^{\frac{1}{6}}

4 x^{2} + 7 x - 2 \leq 0

7 s - 9 < 6 s - 10

2 x^{2} - 4 x = 1

1 + 7 x = 9 + 5 x

What is x^{-3}my^{-4}z^{-3} ?
The solution to x^{-3}my^{-4}z^{-3} is m/(x^3y^4z^3)