What are the solutions to the equation (36+x^2)/2 =7x-6 ?

The solutions to the equation (36+x^2)/2 =7x-6 are x=8,x=6

Find the zeros of (36+x^2)/2 =7x-6

The zeros of (36+x^2)/2 =7x-6 are x=8,x=6

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\frac{36 + x ^{2}}{2} = 7 x - 6

x = 8, x = 6

Solution steps

\frac{36 + x ^{2}}{2} = 7 x - 6

Multiply both sides by

2

36 + x^{2} = 14 x - 12

Move

12

to the left side

x^{2} + 48 = 14 x

Move

14 x

to the left side

x^{2} + 48 - 14 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 14 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 48}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 48 = 2

x_{1, 2} = \frac{- ( - 14 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2}{2 \cdot 1} : 8

x = \frac{- ( - 14 ) - 2}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

x = 8, x = 6

(\frac{1}{8})^{- 3}

π^{- 1}

d (10 d - 9) + 1 = 0

y^{2} - 4 y = 0

\frac{1000 0 ^{2} \cdot 1.5 \cdot 1 0 ^{- 12}}{2.8}

What are the solutions to the equation (36+x^2)/2 =7x-6 ?
The solutions to the equation (36+x^2)/2 =7x-6 are x=8,x=6
Find the zeros of (36+x^2)/2 =7x-6
The zeros of (36+x^2)/2 =7x-6 are x=8,x=6