What are the solutions to the equation 5x^2+26x+5=0 ?

The solutions to the equation 5x^2+26x+5=0 are x=-1/5 ,x=-5

Find the zeros of 5x^2+26x+5=0

The zeros of 5x^2+26x+5=0 are x=-1/5 ,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} + 26 x + 5 = 0

x = - \frac{1}{5}, x = - 5

Decimal Notation

x = - 0.2, x = - 5

Solution steps

5 x^{2} + 26 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

2 6^{2} - 4 \cdot 5 \cdot 5 = 24

x_{1, 2} = \frac{- 26 \pm 24}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 26 + 24}{2 \cdot 5}, x_{2} = \frac{- 26 - 24}{2 \cdot 5}

x = \frac{- 26 + 24}{2 \cdot 5} : - \frac{1}{5}

x = \frac{- 26 - 24}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = - 5

x^{9} - x^{6} - x^{3} + 1

1 = \frac{1}{5} (x - 25)

5 (2 x + 1) = 6 x + 13

e^{2} x - 9 e x + 20 = 0

- \frac{\frac{16}{21}}{( - \frac{8}{3} )}

What are the solutions to the equation 5x^2+26x+5=0 ?
The solutions to the equation 5x^2+26x+5=0 are x=-1/5 ,x=-5
Find the zeros of 5x^2+26x+5=0
The zeros of 5x^2+26x+5=0 are x=-1/5 ,x=-5