What are the solutions to the equation s^2-27s=0 ?

The solutions to the equation s^2-27s=0 are s=27,s=0

Find the zeros of s^2-27s=0

The zeros of s^2-27s=0 are s=27,s=0

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s^{2} - 27 s = 0

s = 27, s = 0

Solution steps

s^{2} - 27 s = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 27)^{2} - 4 \cdot 1 \cdot 0 = 27

s_{1, 2} = \frac{- ( - 27 ) \pm 27}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 27 ) + 27}{2 \cdot 1}, s_{2} = \frac{- ( - 27 ) - 27}{2 \cdot 1}

s = \frac{- ( - 27 ) + 27}{2 \cdot 1} : 27

s = \frac{- ( - 27 ) - 27}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

s = 27, s = 0

\frac{1}{\frac{1}{20} + \frac{1}{20}}

3 x = 4

5 \cdot \frac{1}{5} + \frac{1}{5} \cdot 15

\frac{1}{5} - 1

y^{2} - 8 y - 5 = 0

What are the solutions to the equation s^2-27s=0 ?
The solutions to the equation s^2-27s=0 are s=27,s=0
Find the zeros of s^2-27s=0
The zeros of s^2-27s=0 are s=27,s=0