What are the solutions to the equation -12x^2=28x ?

The solutions to the equation -12x^2=28x are x=0,x=-7/3

Find the zeros of -12x^2=28x

The zeros of -12x^2=28x are x=0,x=-7/3

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- 12 x^{2} = 28 x

x = 0, x = - \frac{7}{3}

Decimal Notation

x = 0, x = - 2.33333 \dots

Solution steps

- 12 x^{2} = 28 x

Move

28 x

to the left side

- 12 x^{2} - 28 x = 0

Factor

- 12 x^{2} - 28 x : - 4 x (3 x + 7)

- 4 x (3 x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x + 7 = 0

Solve

3 x + 7 = 0 : x = - \frac{7}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{7}{3}

\frac{x + 6}{2} > 4 - x - \frac{2 x - 3}{4}

\frac{1}{2} (2) + 3

6 x^{2} + 6 x - 120

∣ x + 2 ∣ \geq - 9

(- 9 - i) + (11 + 6 i)

What are the solutions to the equation -12x^2=28x ?
The solutions to the equation -12x^2=28x are x=0,x=-7/3
Find the zeros of -12x^2=28x
The zeros of -12x^2=28x are x=0,x=-7/3