What are the solutions to the equation (2x-12)x=0 ?

The solutions to the equation (2x-12)x=0 are x=6,x=0

Find the zeros of (2x-12)x=0

The zeros of (2x-12)x=0 are x=6,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 x - 12) x = 0

x = 6, x = 0

Solution steps

(2 x - 12) x = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 12 = 0 or x = 0

Solve

2 x - 12 = 0 : x = 6

The solutions to the quadratic equation are:

x = 6, x = 0

2 - x^{3} \geq 10

0 = - 36 + 13.21 x + \frac{1}{2} (9.8) x^{2}

\frac{1 - \frac{y}{y + x}}{1 - \frac{y}{y - x}}

- (\frac{36}{49})^{\frac{1}{2}}

\frac{1 - i}{1 + 3 i}

What are the solutions to the equation (2x-12)x=0 ?
The solutions to the equation (2x-12)x=0 are x=6,x=0
Find the zeros of (2x-12)x=0
The zeros of (2x-12)x=0 are x=6,x=0