What are the solutions to the equation -10x^2+12x-9=0 ?

The solutions to the equation -10x^2+12x-9=0 are x= 3/5-i(3sqrt(6))/(10),x= 3/5+i(3sqrt(6))/(10)

Find the zeros of -10x^2+12x-9=0

The zeros of -10x^2+12x-9=0 are x= 3/5-i(3sqrt(6))/(10),x= 3/5+i(3sqrt(6))/(10)

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- 10 x^{2} + 12 x - 9 = 0

x = \frac{3}{5} - i \frac{3 6}{10}, x = \frac{3}{5} + i \frac{3 6}{10}

Solution steps

- 10 x^{2} + 12 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 10 ) ( - 9 )}{2 ( - 10 )}

Simplify

1 2^{2} - 4 (- 10) (- 9) : 66 i

x_{1, 2} = \frac{- 12 \pm 6 6 i}{2 ( - 10 )}

Separate the solutions

x_{1} = \frac{- 12 + 6 6 i}{2 ( - 10 )}, x_{2} = \frac{- 12 - 6 6 i}{2 ( - 10 )}

x = \frac{- 12 + 6 6 i}{2 ( - 10 )} : \frac{3}{5} - i \frac{3 6}{10}

x = \frac{- 12 - 6 6 i}{2 ( - 10 )} : \frac{3}{5} + i \frac{3 6}{10}

The solutions to the quadratic equation are:

x = \frac{3}{5} - i \frac{3 6}{10}, x = \frac{3}{5} + i \frac{3 6}{10}

\frac{9}{4} - 3

4 t^{2} - 16

- x + 6 = - 4

\frac{1}{\frac{x}{y}}

\frac{6 ^{12}}{6 ^{10}}

What are the solutions to the equation -10x^2+12x-9=0 ?
The solutions to the equation -10x^2+12x-9=0 are x= 3/5-i(3sqrt(6))/(10),x= 3/5+i(3sqrt(6))/(10)
Find the zeros of -10x^2+12x-9=0
The zeros of -10x^2+12x-9=0 are x= 3/5-i(3sqrt(6))/(10),x= 3/5+i(3sqrt(6))/(10)