What are the solutions to the equation -2x^2+7x+3=0 ?

The solutions to the equation -2x^2+7x+3=0 are x=-(-7+sqrt(73))/4 ,x=(7+sqrt(73))/4

Find the zeros of -2x^2+7x+3=0

The zeros of -2x^2+7x+3=0 are x=-(-7+sqrt(73))/4 ,x=(7+sqrt(73))/4

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- 2 x^{2} + 7 x + 3 = 0

x = - \frac{- 7 + 73}{4}, x = \frac{7 + 73}{4}

Decimal Notation

x = - 0.38600 \dots, x = 3.88600 \dots

Solution steps

- 2 x^{2} + 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 2 ) \cdot 3}{2 ( - 2 )}

7^{2} - 4 (- 2) \cdot 3 = 73

x_{1, 2} = \frac{- 7 \pm 73}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 7 + 73}{2 ( - 2 )}, x_{2} = \frac{- 7 - 73}{2 ( - 2 )}

x = \frac{- 7 + 73}{2 ( - 2 )} : - \frac{- 7 + 73}{4}

x = \frac{- 7 - 73}{2 ( - 2 )} : \frac{7 + 73}{4}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 73}{4}, x = \frac{7 + 73}{4}

2 x^{2} - x + 8 = 0

- \frac{6}{7} - 1

80000 \cdot \frac{1}{( 1 + 0.06 ) ^{30}}

- 16 t^{2} - 8 t + 64

\frac{4}{11}

What are the solutions to the equation -2x^2+7x+3=0 ?
The solutions to the equation -2x^2+7x+3=0 are x=-(-7+sqrt(73))/4 ,x=(7+sqrt(73))/4
Find the zeros of -2x^2+7x+3=0
The zeros of -2x^2+7x+3=0 are x=-(-7+sqrt(73))/4 ,x=(7+sqrt(73))/4