What is (2x+5)(2x-3)>= 3x-12 ?

The solution to (2x+5)(2x-3)>= 3x-12 is x = 3/4

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(2x+5)(2x-3)>= 3x-12

(2 x + 5) (2 x - 3) \geq 3 x - 12

x \leq - 1 or x \geq \frac{3}{4}

Interval Notation

(- \infty, - 1] \cup [\frac{3}{4}, \infty)

Decimal Notation

x \leq - 1 or x \geq 0.75

Solution steps

(2 x + 5) (2 x - 3) \geq 3 x - 12

Rewrite in standard form

4 x^{2} + x - 3 \geq 0

Factor

4 x^{2} + x - 3 : (4 x - 3) (x + 1)

(4 x - 3) (x + 1) \geq 0

Identify the intervals

x \leq - 1 or x \geq \frac{3}{4}

35 x^{2} + 25

10 = 8 h

- 95 = - 10 x + 5

x^{2} - 2 = 0

(\frac{9 ^{3}}{6 ^{3}})^{- \frac{1}{3}}

What is (2x+5)(2x-3)>= 3x-12 ?
The solution to (2x+5)(2x-3)>= 3x-12 is x<=-1\lor x>= 3/4