What are the solutions to the equation 5x^2-17x+6=0 ?

The solutions to the equation 5x^2-17x+6=0 are x=3,x= 2/5

Find the zeros of 5x^2-17x+6=0

The zeros of 5x^2-17x+6=0 are x=3,x= 2/5

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5 x^{2} - 17 x + 6 = 0

x = 3, x = \frac{2}{5}

Decimal Notation

x = 3, x = 0.4

Solution steps

5 x^{2} - 17 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

(- 17)^{2} - 4 \cdot 5 \cdot 6 = 13

x_{1, 2} = \frac{- ( - 17 ) \pm 13}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 13}{2 \cdot 5}, x_{2} = \frac{- ( - 17 ) - 13}{2 \cdot 5}

x = \frac{- ( - 17 ) + 13}{2 \cdot 5} : 3

x = \frac{- ( - 17 ) - 13}{2 \cdot 5} : \frac{2}{5}

The solutions to the quadratic equation are:

x = 3, x = \frac{2}{5}

18 r^{2} - 8

2 (x - 1)^{2} + 24 = 0

b - 1 < - 11

lo g_{7} (9)

- 2 ∣ 6 v + 10 ∣ = - 22

What are the solutions to the equation 5x^2-17x+6=0 ?
The solutions to the equation 5x^2-17x+6=0 are x=3,x= 2/5
Find the zeros of 5x^2-17x+6=0
The zeros of 5x^2-17x+6=0 are x=3,x= 2/5