What is x^2+1>|-2x+1| ?

The solution to x^2+1>|-2x+1| is x 0

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x^2+1>|-2x+1|

x^{2} + 1 > ∣ - 2 x + 1 ∣

x < - 2 or x > 0

Interval Notation

(- \infty, - 2) \cup (0, \infty)

Solution steps

x^{2} + 1 > ∣ - 2 x + 1 ∣

Find positive and negative intervals

x \leq \frac{1}{2}, x > \frac{1}{2}

Solve the inequality for each interval

(x < - 2 or 0 < x \leq \frac{1}{2}) or x > \frac{1}{2}

Merge Overlapping Intervals

x < - 2 or x > 0

\frac{20 !}{6 ! ( 20 - 6 ) !}

30!

5000 \cdot 28 \cdot 7.142857143

27 x^{3} + 216

5 x + 13 < 48