What are the solutions to the equation 4x^2+17x+14=0 ?

The solutions to the equation 4x^2+17x+14=0 are x=(-17+sqrt(65))/8 ,x=(-17-sqrt(65))/8

Find the zeros of 4x^2+17x+14=0

The zeros of 4x^2+17x+14=0 are x=(-17+sqrt(65))/8 ,x=(-17-sqrt(65))/8

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4 x^{2} + 17 x + 14 = 0

x = \frac{- 17 + 65}{8}, x = \frac{- 17 - 65}{8}

Decimal Notation

x = - 1.11721 \dots, x = - 3.13278 \dots

Solution steps

4 x^{2} + 17 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 4 \cdot 14}{2 \cdot 4}

1 7^{2} - 4 \cdot 4 \cdot 14 = 65

x_{1, 2} = \frac{- 17 \pm 65}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 17 + 65}{2 \cdot 4}, x_{2} = \frac{- 17 - 65}{2 \cdot 4}

x = \frac{- 17 + 65}{2 \cdot 4} : \frac{- 17 + 65}{8}

x = \frac{- 17 - 65}{2 \cdot 4} : \frac{- 17 - 65}{8}

The solutions to the quadratic equation are:

x = \frac{- 17 + 65}{8}, x = \frac{- 17 - 65}{8}

- 3 + 3 x^{5}

5 x = 3 x - 10 + 2 x

- 2 y = - 8

\frac{1}{4} (8 x + 16) = 4 x

15 x^{2} - 26 x + 8

What are the solutions to the equation 4x^2+17x+14=0 ?
The solutions to the equation 4x^2+17x+14=0 are x=(-17+sqrt(65))/8 ,x=(-17-sqrt(65))/8
Find the zeros of 4x^2+17x+14=0
The zeros of 4x^2+17x+14=0 are x=(-17+sqrt(65))/8 ,x=(-17-sqrt(65))/8