What are the solutions to the equation 14w=-16-3w^2 ?

The solutions to the equation 14w=-16-3w^2 are w=-8/3 ,w=-2

Find the zeros of 14w=-16-3w^2

The zeros of 14w=-16-3w^2 are w=-8/3 ,w=-2

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14 w = - 16 - 3 w^{2}

w = - \frac{8}{3}, w = - 2

Decimal Notation

w = - 2.66666 \dots, w = - 2

Solution steps

14 w = - 16 - 3 w^{2}

Switch sides

- 16 - 3 w^{2} = 14 w

Move

14 w

to the left side

- 16 - 3 w^{2} - 14 w = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 w^{2} - 14 w - 16 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 ( - 3 ) ( - 16 )}{2 ( - 3 )}

(- 14)^{2} - 4 (- 3) (- 16) = 2

w_{1, 2} = \frac{- ( - 14 ) \pm 2}{2 ( - 3 )}

Separate the solutions

w_{1} = \frac{- ( - 14 ) + 2}{2 ( - 3 )}, w_{2} = \frac{- ( - 14 ) - 2}{2 ( - 3 )}

w = \frac{- ( - 14 ) + 2}{2 ( - 3 )} : - \frac{8}{3}

w = \frac{- ( - 14 ) - 2}{2 ( - 3 )} : - 2

The solutions to the quadratic equation are:

w = - \frac{8}{3}, w = - 2

x^{2} - 3 x - 4 \leq 0

\frac{3}{4} - \frac{5}{18}

- (\frac{3}{5})^{4}

\frac{3 y}{10} - 3 = \frac{y}{5} + 5

\frac{4 a}{a ^{2}} - \frac{7}{8 a}

What are the solutions to the equation 14w=-16-3w^2 ?
The solutions to the equation 14w=-16-3w^2 are w=-8/3 ,w=-2
Find the zeros of 14w=-16-3w^2
The zeros of 14w=-16-3w^2 are w=-8/3 ,w=-2