What are the solutions to the equation r^2-0.2r+0.01=0 ?

The solutions to the equation r^2-0.2r+0.01=0 are r= 1/10

Find the zeros of r^2-0.2r+0.01=0

The zeros of r^2-0.2r+0.01=0 are r= 1/10

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r^{2} - 0.2 r + 0.01 = 0

r = \frac{1}{10}

Decimal Notation

r = 0.1

Solution steps

r^{2} - 0.2 r + 0.01 = 0

Multiply both sides by

100

100 r^{2} - 20 r + 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 100 \cdot 1}{2 \cdot 100}

(- 20)^{2} - 4 \cdot 100 \cdot 1 = 0

r_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 100}

r = \frac{- ( - 20 )}{2 \cdot 100}

\frac{- ( - 20 )}{2 \cdot 100} = \frac{1}{10}

r = \frac{1}{10}

The solution to the quadratic equation is:

r = \frac{1}{10}

2 x^{2} + 6 x - 9 < 0

- 9 m - 27 n

2 x - 16 = 2

100 m^{4} - 81

24 x^{2} y - 6 y

What are the solutions to the equation r^2-0.2r+0.01=0 ?
The solutions to the equation r^2-0.2r+0.01=0 are r= 1/10
Find the zeros of r^2-0.2r+0.01=0
The zeros of r^2-0.2r+0.01=0 are r= 1/10