What are the solutions to the equation 1/2 x^2+23=28 ?

The solutions to the equation 1/2 x^2+23=28 are x=sqrt(10),x=-sqrt(10)

Find the zeros of 1/2 x^2+23=28

The zeros of 1/2 x^2+23=28 are x=sqrt(10),x=-sqrt(10)

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\frac{1}{2} x^{2} + 23 = 28

x = 10, x = - 10

Decimal Notation

x = 3.16227 \dots, x = - 3.16227 \dots

Solution steps

\frac{1}{2} x^{2} + 23 = 28

Move

23

to the right side

\frac{1}{2} x^{2} = 5

Multiply both sides by

2

x^{2} = 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 10, x = - 10

0^{1}

- 2 (w + 4) + 9 < - 11

\frac{m ^{2} - 64}{8 + m}

8 k^{2} - 8 = 120

p^{2} - 8 p + 7

What are the solutions to the equation 1/2 x^2+23=28 ?
The solutions to the equation 1/2 x^2+23=28 are x=sqrt(10),x=-sqrt(10)
Find the zeros of 1/2 x^2+23=28
The zeros of 1/2 x^2+23=28 are x=sqrt(10),x=-sqrt(10)