What are the solutions to the equation 3q^2-5q-6=-3q^2 ?

The solutions to the equation 3q^2-5q-6=-3q^2 are q= 3/2 ,q=-2/3

Find the zeros of 3q^2-5q-6=-3q^2

The zeros of 3q^2-5q-6=-3q^2 are q= 3/2 ,q=-2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 q^{2} - 5 q - 6 = - 3 q^{2}

q = \frac{3}{2}, q = - \frac{2}{3}

Decimal Notation

q = 1.5, q = - 0.66666 \dots

Solution steps

3 q^{2} - 5 q - 6 = - 3 q^{2}

Move

3 q^{2}

to the left side

6 q^{2} - 5 q - 6 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 ( - 6 )}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 (- 6) = 13

q_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 6}

Separate the solutions

q_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 6}, q_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 6}

q = \frac{- ( - 5 ) + 13}{2 \cdot 6} : \frac{3}{2}

q = \frac{- ( - 5 ) - 13}{2 \cdot 6} : - \frac{2}{3}

The solutions to the quadratic equation are:

q = \frac{3}{2}, q = - \frac{2}{3}

- \frac{1}{7} ab - \frac{1}{14} ab - \frac{1}{28} ab - ab

\frac{82 + 78 + 76 + 82 + 2 x}{6} = 80

81 x^{5} - 625 x

n^{4} + 6 n^{3} + 11 n^{2} + 6 n

(\frac{π}{2})^{3}

What are the solutions to the equation 3q^2-5q-6=-3q^2 ?
The solutions to the equation 3q^2-5q-6=-3q^2 are q= 3/2 ,q=-2/3
Find the zeros of 3q^2-5q-6=-3q^2
The zeros of 3q^2-5q-6=-3q^2 are q= 3/2 ,q=-2/3