What are the solutions to the equation 4x^2=23x+72 ?

The solutions to the equation 4x^2=23x+72 are x=8,x=-9/4

Find the zeros of 4x^2=23x+72

The zeros of 4x^2=23x+72 are x=8,x=-9/4

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4 x^{2} = 23 x + 72

x = 8, x = - \frac{9}{4}

Decimal Notation

x = 8, x = - 2.25

Solution steps

4 x^{2} = 23 x + 72

Move

72

to the left side

4 x^{2} - 72 = 23 x

Move

23 x

to the left side

4 x^{2} - 72 - 23 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 23 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 4 ( - 72 )}{2 \cdot 4}

(- 23)^{2} - 4 \cdot 4 (- 72) = 41

x_{1, 2} = \frac{- ( - 23 ) \pm 41}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 41}{2 \cdot 4}, x_{2} = \frac{- ( - 23 ) - 41}{2 \cdot 4}

x = \frac{- ( - 23 ) + 41}{2 \cdot 4} : 8

x = \frac{- ( - 23 ) - 41}{2 \cdot 4} : - \frac{9}{4}

The solutions to the quadratic equation are:

x = 8, x = - \frac{9}{4}

- 21 = y - 17

6 a^{2} + 17 a + 5

3 - \frac{4}{5}

\frac{3}{4} x = - 9

∣ x + 1 ∣ > 8

What are the solutions to the equation 4x^2=23x+72 ?
The solutions to the equation 4x^2=23x+72 are x=8,x=-9/4
Find the zeros of 4x^2=23x+72
The zeros of 4x^2=23x+72 are x=8,x=-9/4