What is factor 20x^2+21x-5 ?

The solution to factor 20x^2+21x-5 is (5x-1)(4x+5)

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factor 20x^2+21x-5

factor

20 x^{2} + 21 x - 5

(5 x - 1) (4 x + 5)

Solution steps

20 x^{2} + 21 x - 5

Break the expression into groups

= (20 x^{2} - 4 x) + (25 x - 5)

Factor out

4 x

from

20 x^{2} - 4 x : 4 x (5 x - 1)

Factor out

5

from

25 x - 5 : 5 (5 x - 1)

= 4 x (5 x - 1) + 5 (5 x - 1)

Factor out common term

5 x - 1

= (5 x - 1) (4 x + 5)

\frac{7 ^{- 3}}{7 ^{5}}

4 x + 3 = 15

∣ x + 9 ∣ \leq 9

36 \geq - 46

\frac{a}{2} > 2