What are the solutions to the equation 0=x^2+2x+1 ?

The solutions to the equation 0=x^2+2x+1 are x=-1

Find the zeros of 0=x^2+2x+1

The zeros of 0=x^2+2x+1 are x=-1

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0 = x^{2} + 2 x + 1

x = - 1

Solution steps

0 = x^{2} + 2 x + 1

Switch sides

x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

x = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

∣ x + 7 ∣ > 5

\frac{4}{5} + \frac{2}{5}

∣ x + 7 ∣ < 3

2 - (x + 3) - (6 - x + 2) = 2 x - 1

0.5 d - 3 d + 5 = 0

What are the solutions to the equation 0=x^2+2x+1 ?
The solutions to the equation 0=x^2+2x+1 are x=-1
Find the zeros of 0=x^2+2x+1
The zeros of 0=x^2+2x+1 are x=-1