What are the solutions to the equation 3r^2+2r=0.375 ?

The solutions to the equation 3r^2+2r=0.375 are r=(-4+sqrt(34))/(12),r=-(4+sqrt(34))/(12)

Find the zeros of 3r^2+2r=0.375

The zeros of 3r^2+2r=0.375 are r=(-4+sqrt(34))/(12),r=-(4+sqrt(34))/(12)

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3 r^{2} + 2 r = 0.375

r = \frac{- 4 + 34}{12}, r = - \frac{4 + 34}{12}

Decimal Notation

r = 0.15257 \dots, r = - 0.81924 \dots

Solution steps

3 r^{2} + 2 r = 0.375

Multiply both sides by

1000

3000 r^{2} + 2000 r = 375

Move

375

to the left side

3000 r^{2} + 2000 r - 375 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 2000 \pm 200 0 ^{2} - 4 \cdot 3000 ( - 375 )}{2 \cdot 3000}

200 0^{2} - 4 \cdot 3000 (- 375) = 50034

r_{1, 2} = \frac{- 2000 \pm 500 34}{2 \cdot 3000}

Separate the solutions

r_{1} = \frac{- 2000 + 500 34}{2 \cdot 3000}, r_{2} = \frac{- 2000 - 500 34}{2 \cdot 3000}

r = \frac{- 2000 + 500 34}{2 \cdot 3000} : \frac{- 4 + 34}{12}

r = \frac{- 2000 - 500 34}{2 \cdot 3000} : - \frac{4 + 34}{12}

The solutions to the quadratic equation are:

r = \frac{- 4 + 34}{12}, r = - \frac{4 + 34}{12}

x^{4} + 25 x^{2}

6 - \frac{x}{11} = 7

\frac{3}{5} \times \frac{3}{2}

24 x^{2} - 11 x - 3 = 3 x

25 + 70 x + 49 x^{2}

What are the solutions to the equation 3r^2+2r=0.375 ?
The solutions to the equation 3r^2+2r=0.375 are r=(-4+sqrt(34))/(12),r=-(4+sqrt(34))/(12)
Find the zeros of 3r^2+2r=0.375
The zeros of 3r^2+2r=0.375 are r=(-4+sqrt(34))/(12),r=-(4+sqrt(34))/(12)