What are the solutions to the equation 25x^2-10x+2=0 ?

The solutions to the equation 25x^2-10x+2=0 are x= 1/5+i 1/5 ,x= 1/5-i 1/5

Find the zeros of 25x^2-10x+2=0

The zeros of 25x^2-10x+2=0 are x= 1/5+i 1/5 ,x= 1/5-i 1/5

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25 x^{2} - 10 x + 2 = 0

x = \frac{1}{5} + i \frac{1}{5}, x = \frac{1}{5} - i \frac{1}{5}

Solution steps

25 x^{2} - 10 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 25 \cdot 2}{2 \cdot 25}

Simplify

(- 10)^{2} - 4 \cdot 25 \cdot 2 : 10 i

x_{1, 2} = \frac{- ( - 10 ) \pm 10 i}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 10 i}{2 \cdot 25}, x_{2} = \frac{- ( - 10 ) - 10 i}{2 \cdot 25}

x = \frac{- ( - 10 ) + 10 i}{2 \cdot 25} : \frac{1}{5} + i \frac{1}{5}

x = \frac{- ( - 10 ) - 10 i}{2 \cdot 25} : \frac{1}{5} - i \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{1}{5} + i \frac{1}{5}, x = \frac{1}{5} - i \frac{1}{5}

\frac{1}{4} + \frac{3}{2}

\frac{x ^{2}}{2} = 18

\frac{6}{- 7}

\frac{x}{17} = 4

3 x y - 2 x - 9 y + 6

What are the solutions to the equation 25x^2-10x+2=0 ?
The solutions to the equation 25x^2-10x+2=0 are x= 1/5+i 1/5 ,x= 1/5-i 1/5
Find the zeros of 25x^2-10x+2=0
The zeros of 25x^2-10x+2=0 are x= 1/5+i 1/5 ,x= 1/5-i 1/5