What are the solutions to the equation 6x^2-41x-7=0 ?

The solutions to the equation 6x^2-41x-7=0 are x=7,x=-1/6

Find the zeros of 6x^2-41x-7=0

The zeros of 6x^2-41x-7=0 are x=7,x=-1/6

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6 x^{2} - 41 x - 7 = 0

x = 7, x = - \frac{1}{6}

Decimal Notation

x = 7, x = - 0.16666 \dots

Solution steps

6 x^{2} - 41 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 41 ) \pm ( - 41 ) ^{2} - 4 \cdot 6 ( - 7 )}{2 \cdot 6}

(- 41)^{2} - 4 \cdot 6 (- 7) = 43

x_{1, 2} = \frac{- ( - 41 ) \pm 43}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 41 ) + 43}{2 \cdot 6}, x_{2} = \frac{- ( - 41 ) - 43}{2 \cdot 6}

x = \frac{- ( - 41 ) + 43}{2 \cdot 6} : 7

x = \frac{- ( - 41 ) - 43}{2 \cdot 6} : - \frac{1}{6}

The solutions to the quadratic equation are:

x = 7, x = - \frac{1}{6}

16 t^{2} - 23 t + 8 = 0

∣ x + 4 ∣ > 2

(\frac{4}{5})^{- 1}

\frac{x ^{2} - 4 x - 5}{x - 1} \leq 0

\frac{1}{10} = x

What are the solutions to the equation 6x^2-41x-7=0 ?
The solutions to the equation 6x^2-41x-7=0 are x=7,x=-1/6
Find the zeros of 6x^2-41x-7=0
The zeros of 6x^2-41x-7=0 are x=7,x=-1/6